`<=> (x+1)/2022 + 1 + (x+2)/2021 + 1 = (x+2020)/3 +1 + (x+2019)/4 + 1`
`<=> (x + 2023)/2022 + (x+2023)/2021 = (x+2023)/3 + (x+2019)/4`.
`<=> (x+2023)(1/2023 + 1/2021 - 1/3 - 1/4) = 0`
`<=> x + 2023 = 0 ( 1/2023 + 1/2021 - 1/3 - 1/4 ne 0 )`.
`=> x = 0 - 2023`.
`=> x = -2023`.
Vậy `x = -2023`.
`( x + 1 )/2022 + ( x + 2 )/2021 = ( x+2020 )/3 + ( x+2019 )/4`
`=> ( x + 1 )/2022 + ( x + 2 )/2021 - (( x+2020 )/3 + ( x+2019 )/4 ) = 0`
`=> ( x + 1 )/2022 + 1 + ( x + 2 )/2021 - ( ( x+2020 )/3+1 + ( x+2019 )/4+1)=0`
`=> ( x + 2023 )/2022 + ( x + 2023 )/2021 - ( ( x + 2023 )/3 + ( x + 2023 )/4 ) =0`
`=> ( x + 2023)[1/2021 + 1/2022 - ( 1/3 + 1/4 )] = 0`
Do `1/2021 + 1/2022 - ( 1/3 + 1/4 ) \ne 0`
`=> x + 2023=0`
`=> x=-2023`