Gọi H là trung điểm AB \(\Rightarrow IH\perp AB\Rightarrow IH=d\left(I;\Delta\right)\)
\(\Rightarrow IH=\dfrac{\left|-2.2+3.1-6\right|}{\sqrt{2^2+3^2}}=\dfrac{7}{\sqrt{13}}\)
\(\widehat{AIB}=120^0\Rightarrow\widehat{AIH}=60^0\)
\(\Rightarrow R=IA=\dfrac{IH}{cos60^0}=\dfrac{14}{\sqrt{13}}\)
Phương trình đường tròn: \(\left(x+2\right)^2+\left(y-1\right)^2=\dfrac{196}{13}\)