Question

Answer 1

Đk: x khác 0, x khác 2

\(\dfrac{x+2}{x}\)=\(\dfrac{2x+3}{2x-4}\)

<=>\(\dfrac{\left(x+2\right)\left(2x-4\right)}{x\left(2x-4\right)}\)= \(\dfrac{x\left(2x+3\right)}{x\left(2x-4\right)}\)

<=> (x+2)(2x-4)= x(2x+3)

<=> 2x^₂ -4x +4x -8 = 2x²+3x

<=> 2x²-4x+4x-8-2x²-3x= 0

<=> -3x-8=0

<=> -3x=8

<=> x=\(\)\(\dfrac{-8}{3}\)

S={\(\dfrac{-8}{3}\)}