Question

Answer 1

a)\(-5x-5+5x^2\)

b)\(-5x^2+5+5x\)

Answer 2

\(\text{M-N ta có:}\)

\(\text{​​}\text{​​}M-N=\)\(4x^3-5x+3-\left(4x^3-5x^2+8\right)\)

\(\text{​​}\text{​​}M-N=\)\(4x^3-5x+3-4x^3+5x^2-8\)

\(\text{​​}\text{​​}M-N=\)\(5x^2-5x-5\)

\(\text{​​}\text{​​}M-N=\)\(x^2-x-1\)

\(\text{Vậy M-N=x^2-x-1}\)

\(\text{N-M ta có:}\)

\(N-M=\)\(4x^3-5x^2+8-\left(4x^3-5x+3\right)\)​​

\(N-M=4x^3-5x^2+8-4x^3+5x-3\)

\(N-M=-5x^2+5x-5\)

\(N-M=-x^2+x-1\)

\(\text{Vậy N-M=-x^2+x-1}\)