Question

Answer 1

a, \(M=\left(3+\dfrac{1}{2}-1\right)x^2y^3=\dfrac{5}{2}x^2y^3z\)

b, Thay x = -1 ; y = 1/2 ; z = 3 ta đc 

\(\dfrac{5}{2}.1.\dfrac{1}{8}.3=\dfrac{15}{16}\)

Answer 2

a: \(M=x^2y^3z\left(3+\dfrac{1}{2}-1\right)=\dfrac{5}{2}x^2y^3z\)

b: \(M=\dfrac{5}{2}\cdot\left(-1\right)^2\cdot\dfrac{1}{8}\cdot3=\dfrac{5}{16}\cdot3=\dfrac{15}{16}\)