\(n_{O_2}=\dfrac{m_{O_2}}{M_{O_2}}=\dfrac{19,2}{32}=0,6mol\)
\(4Al+3O_2\rightarrow\left(t^o\right)2Al_2O_3\)
0,8 0,6 ( mol )
\(m_{Al}=n_{Al}.M_{Al}=0,8.27=21,6g\)
\(4Al+3O_2\rightarrow2Al_2O_3\)
\(n_{O_2}=\dfrac{19.2}{32}=0.6\left(mol\right)\)
\(\Leftrightarrow n_{Al_2O_3}=0.4\left(mol\right)\)
\(\Leftrightarrow n_{Al}=0.8\left(mol\right)\)
\(a=0.8\cdot27=21.6\left(g\right)\)
\(n_{O_2}=\dfrac{19,2}{32}=0,6\left(mol\right)\)
PTHH: \(4Al+3O_2\underrightarrow{t^o}2Al_2O_3\)
0,8 0,6 (mol)
\(m_{Al}=0,8.27=21,6\left(g\right)\)
