Question

Answer 1

a: \(=\dfrac{35}{41}+\dfrac{2}{3}+\dfrac{6}{41}-\dfrac{1}{2}=1+\dfrac{2}{3}-\dfrac{1}{2}=\dfrac{6}{6}+\dfrac{4}{6}-\dfrac{3}{6}=\dfrac{7}{6}\)

b: \(=\dfrac{5}{14}\cdot\dfrac{-14}{35}\cdot\dfrac{50}{9}\cdot\dfrac{-1}{7}\)

\(=\dfrac{-1}{7}\cdot\dfrac{-1}{7}\cdot\dfrac{50}{9}=\dfrac{50}{441}\)

c: \(=\dfrac{3}{5}\left(\dfrac{5}{29}+\dfrac{12}{29}+\dfrac{12}{29}\right)=\dfrac{3}{5}\cdot1=\dfrac{3}{5}\)