Question

Answer 1

\(B=\dfrac{2^{12}\cdot78}{2^{10}\cdot104}+\dfrac{3^{10}\cdot16}{3^9\cdot2^4}=\dfrac{2^{12}\cdot78}{2^{12}\cdot26}+3=3+3=6\)

Answer 2

\(B=\dfrac{2^{12}.13+2^{12}.65}{2^{10}.104}+\dfrac{3^{10}.11+3^{10}.5}{3^9.2^4}\\ =\dfrac{2^{12}.\left(13+65\right)}{2^{10}.\left(2^2.26\right)}+\dfrac{3^{10}.\left(11+5\right)}{3^9.2^4}\\ =\dfrac{2^{12}.\left(26.3\right)}{2^{12}.26}+\dfrac{\left(3^9.3\right).2^4}{3^9.2^4}\\ =3+3=6\)