a) \(-5x-\left(-3\right)=13\)
⇒ \(x=-2\)
c) \(\dfrac{2}{9}+\dfrac{1}{3}:x=\dfrac{5}{9}\)
⇒ \(\dfrac{1}{3}:x=\dfrac{5}{9}-\dfrac{2}{9}=\dfrac{1}{3}\)
⇒ \(x=1\)
i) \(\dfrac{x+2}{5}=\dfrac{2-3x}{3}\)
⇔ \(3x+6=10-15x\)
⇔ \(18x=4\)
⇒ \(x=\dfrac{2}{9}\)
a. \(-5x-\left(-3\right)=13\)
\(-5x+3=13\)
\(-5x=10\)
\(x=-2\)
e. \(\dfrac{2}{9}+\dfrac{1}{3}:x=\dfrac{5}{9}\)
\(\dfrac{1}{3}:x=\dfrac{1}{3}\)
\(x=1\)
i. \(\dfrac{x+2}{5}=\dfrac{2-3x}{3}\)
\(3.\left(x+2\right)=5.\left(2-3x\right)\)
\(3x+6=10-6x\)
\(3x+6x=10-6\)
\(9x=4\)
\(x=\dfrac{4}{9}\)
\(-5x-\left(-3\right)=13.\Leftrightarrow-5x+3=13.\Leftrightarrow x=-2.\\ \dfrac{2}{9}+\dfrac{1}{3}:x=\dfrac{5}{9}.\Leftrightarrow\dfrac{1}{3}:x=\dfrac{1}{3}.\Leftrightarrow x=1.\)
\(\dfrac{x+2}{5}=\dfrac{2-3x}{3}.\Leftrightarrow\dfrac{3x+6-10+15x}{15}=0.\Rightarrow-18x-4=0.\Leftrightarrow x=\dfrac{2}{9}.\)
