\(a.y-\dfrac{3}{4}=\dfrac{2}{7}.\Leftrightarrow y=\dfrac{29}{28}.\\ b.\dfrac{-5}{12}-y=\dfrac{-3}{4}.\Leftrightarrow y=\dfrac{1}{3}.\\ c.3y-\dfrac{1}{8}=\dfrac{-5}{16}.\Leftrightarrow3y=\dfrac{-3}{16}.\Leftrightarrow x=\dfrac{-1}{16}.\\ d.\dfrac{y}{2}-\dfrac{3}{5}=\dfrac{1}{10}.\Leftrightarrow\dfrac{y}{2}=\dfrac{7}{10}.\Leftrightarrow y=\dfrac{7}{5}.\)
1 .
\(a,y=\dfrac{2}{7}+\dfrac{3}{4}\\y=\dfrac{8}{28}+\dfrac{21}{28}\\ y=\dfrac{29}{28}\\ b,y=\dfrac{-5}{12}-\dfrac{-3}{4}\\ y=\dfrac{-5}{12}-\dfrac{-9}{12}\\ y=\dfrac{4}{12}=\dfrac{1}{3}\\ c,3y=\dfrac{-5}{16}+\dfrac{1}{8}\\ 3y=\dfrac{-5}{16}+\dfrac{2}{16}\\ 3y=\dfrac{-3}{16}\\ y=\dfrac{-3}{16}:3\\ y=\dfrac{-3}{48}\\ d,\dfrac{y}{2}=\dfrac{1}{10}+\dfrac{3}{5}\\ =\dfrac{y}{2}=\dfrac{1}{10}+\dfrac{6}{10}\\\dfrac{y}{2}=\dfrac{7}{10}\Rightarrow7.10=2.7=14\\ \Rightarrow y=1,4\)
a) \(y=\dfrac{2}{7}+\dfrac{3}{4}=\dfrac{29}{28}\)
b) \(y=\dfrac{-5}{12}-\dfrac{-3}{4}=\dfrac{1}{3}\)
c) \(y=\dfrac{\dfrac{-5}{16}+\dfrac{1}{8}}{3}=-\dfrac{1}{16}\)
d) \(y=\left(\dfrac{1}{10}+\dfrac{3}{5}\right).2=\dfrac{7}{5}\)
