Bài 2:
a: \(\Leftrightarrow2x=-\dfrac{3}{2}+\dfrac{6}{5}=-\dfrac{3}{10}\)
hay x=-3/20
b: \(\Leftrightarrow\left|x\right|=\dfrac{5}{12}-\dfrac{1}{3}=\dfrac{1}{12}\)
hay \(x\in\left\{\dfrac{1}{12};-\dfrac{1}{12}\right\}\)
c: \(\Leftrightarrow x\cdot\dfrac{1}{2}=3.2+10=13.2\)
hay x=26,4