\(2\left|x+1\right|-0,5=\sqrt{\dfrac{1}{9}}\)
\(2\left|x+1\right|-\dfrac{1}{2}=\dfrac{1}{3}\)
\(2\left|x+1\right|\) \(=\dfrac{1}{3}+\dfrac{1}{2}=\dfrac{5}{6}\)
\(\left|x+1\right|\) \(=\dfrac{5}{6}.\dfrac{1}{2}=\dfrac{5}{12}\)
\(\text{Vậy }x+1=\dfrac{5}{12}\)
\(x\) \(=\dfrac{5}{12}+\left(-1\right)=\dfrac{-7}{12}\)
\(\text{hoặc }x+1=\dfrac{-5}{12}\)
\(x\) \(=\left(\dfrac{-5}{12}\right)+\left(-1\right)=\dfrac{-17}{12}\)
\(\Rightarrow x\in\left\{\dfrac{-7}{12};\left(\dfrac{-17}{12}\right)\right\}\)