Question

Answer 1

Bài 4: 

a: Xét ΔABM và ΔACM có

AB=AC

AM chung

BM=CM

Do đó: ΔABM=ΔACM

Answer 2

 Bài 1: a) 5¹² : 5¹¹ -\(\dfrac{1}{4}\).\(\sqrt{\dfrac{16}{9}}\)+\(\left(\dfrac{-2}{3}^{ }\right)^2\)

              = 5 - \(\dfrac{1}{4}\).\(\dfrac{4}{3}\)+ \(\dfrac{4}{9}\)

              = 5 - \(\dfrac{1}{3}\)+\(\dfrac{4}{9}\)

              = \(\dfrac{46}{9}\)