\(a,\Rightarrow\dfrac{3}{2}x=\dfrac{1}{4}\Rightarrow x=\dfrac{1}{6}\\ b,\Rightarrow\left[{}\begin{matrix}x-\dfrac{2}{3}=\dfrac{2}{3}\\\dfrac{2}{3}-x=\dfrac{2}{3}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{4}{3}\\x=0\end{matrix}\right.\\ c,\Rightarrow x=\left(1-\dfrac{4}{3}\right)^2+\dfrac{5}{3}-\dfrac{4}{9}=\dfrac{1}{9}-\dfrac{4}{9}+\dfrac{5}{3}=\dfrac{4}{3}\\ d,\Rightarrow x=\dfrac{5^5\cdot7^5\cdot5^{10}}{7^4\cdot5^{18}}=\dfrac{7}{5^3}=\dfrac{7}{125}\)
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