Lời giải:
a. $|\frac{1}{2}x-\frac{1}{6}|=\frac{1}{3}$
\(\Rightarrow \left[\begin{matrix} \frac{1}{2}x-\frac{1}{6}=\frac{1}{3}\\ \frac{1}{2}x-\frac{1}{6}=-\frac{1}{3}\end{matrix}\right.\Leftrightarrow \left[\begin{matrix} x=1\\ x=\frac{-1}{3}\end{matrix}\right. \)
b.
$(4x^2-3)^3+8=0$
$\Leftrightarrow (4x^2-3)^3=-8=(-2)^3$
$\Leftrightarrow 4x^2-3=-2$
$\Leftrightarrow 4x^2=1$
$\Leftrightarrow x^2=\frac{1}{4}=(\frac{1}{2})^2=(\frac{-1}{2})^2$
$\Rightarrow x=\pm \frac{1}{2}$
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