Ta có:
\(f\left(0\right)=3.0^2-0+1=0-0+1=1\\ f\left(-1\right)=3.\left(-1\right)^2-\left(-1\right)+1=3.1+1+1=5\\ f\left(2\right)=3.2^2-2+1=3.4-2+1=12-2+1=9\)
\(f\left(0\right)=3.0^2-0+1=0-0+1=1\\ f\left(-1\right)=3.\left(-1\right)^2-\left(-1\right)+1=3.1+1+1=5\\ f\left(2\right)=3.2^2-2+1=3.4-2+1=12-2+1=11\)