Câu 3:
\(\overrightarrow{AC}-\overrightarrow{AD}=\overrightarrow{DC}\)
\(\overrightarrow{BC}-\overrightarrow{BD}=\overrightarrow{DC}\)
Do đó: \(\overrightarrow{AC}-\overrightarrow{AD}=\overrightarrow{BC}-\overrightarrow{BD}\)
hay \(\overrightarrow{AC}+\overrightarrow{BD}=\overrightarrow{BC}+\overrightarrow{AD}\)