Question

Answer 1

\(\left|2x-1\right|-\dfrac{1}{2}=\dfrac{1}{3}\)

\(\left|2x-1\right|=\dfrac{5}{6}\)

\(\Rightarrow2x-1=\dfrac{5}{6}\)                      hoặc           \(2x-1=-\dfrac{5}{6}\)             

       \(2x=\dfrac{11}{6}\)                                            \(2x=\dfrac{1}{6}\)

        \(x=\dfrac{11}{12}\)                                            \(x=\dfrac{1}{12}\)

Answer 2

|2x-1| = \(\dfrac{1}{3}+\dfrac{1}{2}\)

|2x-1|= \(\dfrac{5}{6}\)

⇒2x-1= \(\dfrac{5}{6}\) hoặc 2x-1= \(\dfrac{-5}{6}\)

TH1:

2x-1= \(\dfrac{5}{6}\)

2x=\(\dfrac{5}{6}\)+1

2x= \(\dfrac{11}{6}\)

x=\(\dfrac{11}{6}\):2

x= \(\dfrac{11}{12}\)

TH2

2x-1=\(\dfrac{-5}{6}\)

2x= \(\dfrac{-5}{6}\)+1

2x= \(\dfrac{1}{6}\)

x= \(\dfrac{1}{6}\):2

x= \(\dfrac{1}{12}\)

Vậy x∈\(\left\{\dfrac{11}{12};\dfrac{1}{12}\right\}\)