Question

Answer 1

\(a,\Rightarrow\left[{}\begin{matrix}5x-1=\dfrac{6}{7}\\1-5x=\dfrac{6}{7}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}5x=\dfrac{13}{7}\\5x=\dfrac{1}{7}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{13}{35}\\x=\dfrac{1}{35}\end{matrix}\right.\\ b,\Rightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{2}{3}\end{matrix}\right.\\ c,\Rightarrow x+1=25\Rightarrow x=24\)

Answer 2

c: \(\Leftrightarrow x+1=25\)

hay x=24