a. \(R=U^2:P=220^2:1000=48,4\Omega\)
b. \(H=\dfrac{Q_{thu}}{Q_{toa}}100\%=\dfrac{mc\Delta t}{UIt}=\dfrac{2,5\cdot4200\cdot80}{220\cdot\left(\dfrac{220}{48,4}\right)\cdot15\cdot60}100\%\approx93,3\%\)
c. \(R=p\dfrac{l}{S}\Rightarrow l=\dfrac{R\cdot S}{p}=\dfrac{48,4\cdot0,2\cdot10^{-6}}{0,4\cdot10^{-6}}=24,2\left(m\right)\)