Question

Answer 1

Dạng 2: 

a: \(\Leftrightarrow x\cdot\dfrac{5}{2}=\dfrac{-3}{10}+\dfrac{4}{5}=\dfrac{1}{2}\)

hay \(x=\dfrac{1}{5}\)

b: \(\Leftrightarrow\left|2x-\dfrac{5}{4}\right|=\dfrac{1}{6}\)

\(\Leftrightarrow\left[{}\begin{matrix}2x-\dfrac{5}{4}=\dfrac{1}{6}\\2x-\dfrac{5}{4}=-\dfrac{1}{6}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=\dfrac{17}{12}\\2x=\dfrac{13}{12}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{17}{24}\\x=\dfrac{13}{24}\end{matrix}\right.\)