\(\Rightarrow\dfrac{2}{9}\cdot3\cdot3^{2a}-4\cdot3^{2a}=-30\\ \Rightarrow\dfrac{2}{3}\cdot3^{2a}-4\cdot3^{2a}=-30\\ \Rightarrow3^{2a}\left(\dfrac{2}{3}-4\right)=-30\\ \Rightarrow3^{2a}=-30:\left(-\dfrac{10}{3}\right)=9=3^2\\ \Rightarrow2a=2\Rightarrow a=1\)