a) Ta có: \(\widehat{CBt}=\widehat{ABt}=\dfrac{\widehat{CBA}}{2}=\dfrac{70^0}{2}=35^0\)
\(\Rightarrow\widehat{CBt}=\widehat{BCy}=35^0\)
Mà 2 góc này so le trong
=> Bt//Cy
b) Ta có: Ax//Cy, Bt//Cy
=> Ax//Bt
\(\Rightarrow\widehat{BAx}=\widehat{ABt}=35^0\)(so le trong)