Question

Answer 1

giúp mình bài 3 voi , thank mn nhieu

 

Answer 2

Bài 3:

a, Vì a⊥c; b⊥c nên a//b

b, Kẻ c//a//b (P∈C)

\(\Rightarrow\widehat{MPc}=\widehat{PMa}=35^0;\widehat{NPc}=\widehat{PNb}=73^0\\ \Rightarrow\widehat{MPN}=\widehat{MPc}+\widehat{NPc}=35^0+73^0=108^0\)