Đặt \(\dfrac{a}{5}=\dfrac{b}{7}=\dfrac{c}{9}=k\)
\(\Leftrightarrow\left\{{}\begin{matrix}a=5k\\b=7k\\c=9k\end{matrix}\right.\)
Ta có: ab=140
\(\Leftrightarrow35k^2=140\)
\(\Leftrightarrow k=2\)
\(\Leftrightarrow\left\{{}\begin{matrix}a=5k=10\\b=7k=14\\c=9k=18\end{matrix}\right.\)