a. Bạn tự vẽ sơ đồ nhé!
b. \(R=R1+R2=10+20=30\Omega\)
c + d. \(I=I1=I2=0,3A\left(R1ntR2\right)\)
\(\Rightarrow\left\{{}\begin{matrix}U=IR=0,3.30=9V\\U1=I1.R1=0,3.10=3V\\U2=I2.R2=0,3.20=6V\end{matrix}\right.\)
e. \(R3=p\dfrac{l}{S}=1,1.10^{-6}\dfrac{6}{0,3.10^{-6}}=22\Omega\)
\(R'=R+R3=30+22=52\Omega\)
\(\Rightarrow I'=U:R'=9:52=\dfrac{9}{52}\simeq0,17A\)
Vậy CĐDĐ sẽ giảm xuống.