ĐKXĐ: x<>3/2
Ta có: \(27:\left(x-\frac32\right)^3=\left(x-\frac32\right):3\)
=>\(\left(x-\frac32\right)^3\cdot\left(x-\frac32\right)=27\cdot3\)
=>\(\left(x-\frac32\right)^4=81\)
=>\(\left[\begin{array}{l}x-\frac32=3\\ x-\frac32=-3\end{array}\right.\Rightarrow\left[\begin{array}{l}x=3+\frac32=\frac92\left(nhận\right)\\ x=-3+\frac32=-\frac32\left(nhận\right)\end{array}\right.\)
