\(1,Sửa:25x^2+10xy+y^2=\left(5x+y\right)^2\\ 2,=\left(x^2-4y^2\right)\left(x^2+4y^2\right)=\left(x-2y\right)\left(x+2y\right)\left(x^2+4y^2\right)\\ 3,=\left(x+1\right)^2-\left(3y+m\right)^2=\left(x+1-3y-m\right)\left(x+1+3y+m\right)\\ 4,=\left(x-y\right)\left(x+y\right)+6\left(x-y\right)=\left(x-y\right)\left(x+y+6\right)\\ 5,=\left(2x+0,1y\right)\left(4x^2-0,2xy+0,01y^2\right)\)
a) \(=\left(5x+1\right)^2\)
b) \(=\left(x^2-4y^2\right)\left(x^2+4y^2\right)=\left(x-2y\right)\left(x+2y\right)\left(x^2+4y^2\right)\)
c) \(=\left(x^2+2x+1\right)-\left(9y^2+6my+m^2\right)\)
\(=\left(x+1\right)^2-\left(3y+m\right)^2=\left(x+1+3y+m\right)\left(x+1-3y-m\right)\)
d) \(=\left(x-y\right)\left(x+y\right)+6\left(x-y\right)=\left(x-y\right)\left(x+y+6\right)\)
e) \(=\left(2x+0,1y\right)\left(4x^2-0,2xy+0,01y^2\right)\)
