Question

Answer 1

giúp mk với

 

 

 

 

Answer 2

Lời giải:
$c\perp a, c\perp b\Rightarrow a\parallel b$

Ta có:

$\widehat{A_1}+\widehat{A_2}=180^0$

$\widehat{A_2}=2\widehat{A_1}$
$\Rightarrow \widehat{A_1}+2\widehat{A_1}=180^0$

$\Leftrightarrow 3\widehat{A_1}=180^0$

$\Leftrightarrow \widehat{A_1}=60^0$

$\widehat{A_2}=2\widehat{A_1}=2.60^0=120^0$

$\widehat{B_2}=\widehat{A_2}=120^0$ (2 góc so le trong)

$\widehat{B_1}=180^0-\widehat{B_2}=180^0-120^0=60^0$