\(1,\\ a,=\dfrac{11}{5}\cdot\dfrac{1}{2}+1=\dfrac{11}{10}+1=\dfrac{21}{10}\\ b,=\dfrac{5}{3}:\dfrac{10}{3}-\dfrac{1}{2}=\dfrac{1}{2}-\dfrac{1}{2}=0\\ c,=\dfrac{1}{2}:\dfrac{7}{4}-\dfrac{7}{3}=\dfrac{2}{7}-\dfrac{7}{3}=-\dfrac{43}{21}\\ d,=-\dfrac{1}{3}+\dfrac{1}{2}+\dfrac{5}{3}=\dfrac{11}{6}\)
\(2,\\ a,\Rightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\\ b,\Rightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=-\dfrac{3}{4}\end{matrix}\right.\\ c,\Rightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=\dfrac{3}{5}\\x+\dfrac{1}{2}=-\dfrac{3}{5}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{10}\\x=-\dfrac{11}{10}\end{matrix}\right.\\ d,\Rightarrow\left[{}\begin{matrix}5-x=\dfrac{4}{3}\\x-5=\dfrac{4}{3}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{11}{3}\\x=\dfrac{19}{3}\end{matrix}\right.\)
