chỉ cần đáp án thôi ạ ko cần cách làm ạ ( kảm ưn )
Bài 3:
Ta có: \(\dfrac{1}{2}-\left(\dfrac{1}{3}+\dfrac{3}{4}\right)\le x\le\dfrac{1}{24}-\left(\dfrac{1}{8}-\dfrac{1}{3}\right)\)
\(\Leftrightarrow\dfrac{6}{12}-\dfrac{4}{12}-\dfrac{9}{12}\le x\le\dfrac{1}{24}-\dfrac{3}{24}+\dfrac{8}{24}\)
\(\Leftrightarrow\dfrac{-7}{12}\le x\le\dfrac{1}{4}\)
\(\Leftrightarrow x\in\left\{-1;0\right\}\)