\(r:\dfrac{3}{7}=\dfrac{5}{9}\)
\(r=\dfrac{5}{9}.\dfrac{3}{7}\)
\(\Rightarrow r=\dfrac{5}{21}\)
\(r=\dfrac{5}{9}\cdot\dfrac{3}{7}=\dfrac{15}{63}=\dfrac{5}{21}\)
Giải:
\(r:\dfrac{3}{7}=\dfrac{5}{9}\)
\(r=\dfrac{5}{9}.\dfrac{3}{7}\)
Vậy \(r=\dfrac{5}{21}\)
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