\(12.\left|\frac{-1}{4}\right|-6^2\left(\frac{1}{3}+\frac{1}{3}\right)^2-x=7\)
\(12.\frac{1}{4}-36.\left(\frac{1}{3}+\frac{1}{3}\right)^2-x=7\)
\(12.\frac{1}{4}-36.\frac{2}{3}^2-x=7\)
\(12.\frac{1}{4}-36.\frac{4}{9}-x=7\)
\(3-16-x=7\)
\(-19-x=7\)
\(x=-19-7\)
\(x=-26\)