`5a)(3×7×8)/(7×8×9)`
`=(3×7×8)/(3×7×8×3)=1/3`
`5b)(x+1)/3=16/24`
`qquad (x+1)/3=(2×8)/(3×8)=2/3`
`qquad x+1=2`
`qquad x=1`
Vậy `x=1`.
a) Ta có: \(A=\dfrac{3\cdot7\cdot8}{7\cdot8\cdot9}\)
\(=\dfrac{3}{9}=\dfrac{1}{3}\)
b) Ta có: \(\dfrac{x+1}{3}=\dfrac{16}{24}\)
\(\Leftrightarrow x+1=2\)
hay x=1
Vậy: x=1
a,=\(\dfrac{3\times7\times8}{7\times8\times9}\)
=\(\dfrac{3\times7\times8}{7\times8\times9}\)
=\(\dfrac{1}{3}\)
b,\(\dfrac{x+1}{3}=\dfrac{16}{24}\)
Ta se co 3-1=2 vay thi x=2
Ta co \(\dfrac{16}{24}\)=\(\dfrac{2\times8}{3\times8}\)
x+1=2
Vay thi x bang 1.
