`x/2+(x+x)/3+(x+x+x)/4`
`=x/2+(2x)/3+(3x)/4`
`=(6x)/12+(8x)/12+(9x)/12`
`=(23x)/12`
giúp mik với nahnh nhé mik cần gấp
xin các bạn đó
Ta có: \(\dfrac{x}{2}+\dfrac{x+x}{3}+\dfrac{x+x+x}{4}=5\dfrac{3}{4}\)
\(\Leftrightarrow\dfrac{1}{2}x+\dfrac{2}{3}x+\dfrac{3}{4}x=\dfrac{23}{4}\)
\(\Leftrightarrow\dfrac{23}{12}x=\dfrac{23}{4}\)
hay x=3
Vậy: x=3