-3/4 + -1/4 + 2/7 + 5/7 + 3/5
SOS mik đn cần gấp ạ
-3/4 + -1/4 + 2/7 + 5/7 + 3/5
SOS mik đn cần gấp ạ
`(-3/4)+(-1/4)+2/7+5/7+3/5`
`=[(-3/4)+(-1/4)]+(2/7+5/7)+3/5`
`=-4/4+7/7+3/5`
`=-1+1+3/5`
`=0+3/5`
`=3/5`
-3/4 + -1/4 + 2/7 + 5/7 + 3/5
= (-3/4 + -1/4) + (2/7 + 5/7) + 3/5
= (-1 + 1) + 3/5
= 0 + 3/5
= 0
(−34)+(−14)+27+57+35(-34)+(-14)+27+57+35
=[(−34)+(−14)]+(27+57)+35=[(-34)+(-14)]+(27+57)+35
=−44+77+35=-44+77+35
=−1+1+35=-1+1+35
=0+35=0+35
=35
13/-10 + -14/25
giải thích ra cho mik nha
\(\dfrac{13}{-10}+\dfrac{-14}{25}=\dfrac{-65}{50}+\dfrac{-28}{50}=\dfrac{-93}{50}\) (quy đồng mẫu số)
2/5 < 1/2^2 +1/3^2 +1/4^2 +...+ 1/9^2 <8/9
1/2^2<1/1*2
1/3^2<1/2*3
...
1/9^2<1/8*9
=>A<1-1/2+1/2-1/3+...+1/8-1/9=8/9
1/2^2>1/2*3
1/3^2>1/3*4
...
1/9^2>1/9*10
=>A>1/2-1/3+1/3-1/4+...+1/9-1/10=2/5
=>2/5<A<8/9
-13/7+3/5+-1/7
\(-\dfrac{13}{7}+\dfrac{3}{5}+\left(-\dfrac{1}{7}\right)\)
\(=-\dfrac{13}{7}+\left(-\dfrac{1}{7}\right)+\dfrac{3}{5}\)
\(=-\dfrac{14}{7}+\dfrac{3}{5}\)
\(=-2+\dfrac{3}{5}\)
\(=-\dfrac{10}{5}+\dfrac{3}{5}\)
\(=-\dfrac{7}{5}\)
\(\dfrac{-13}{7}+\dfrac{3}{5}+\dfrac{-1}{7}\)
\(=\left(\dfrac{-13}{7}+\dfrac{-1}{7}\right)+\dfrac{3}{5}\)
\(=\dfrac{-13+\left(-1\right)}{7}+\dfrac{3}{5}\)
\(=-2+\dfrac{3}{5}\)
\(=\dfrac{-2}{1}+\dfrac{3}{5}\)
\(=\dfrac{-10}{5}+\dfrac{3}{5}\)
\(=\dfrac{-7}{5}\)
f) \(\dfrac{x+1}{x-3}=\dfrac{x+7}{x-2}\)
\(\dfrac{x+1}{x-3}=\dfrac{x+7}{x-2}\) ĐK : \(\left\{{}\begin{matrix}x-3\ne0\\x-2\ne0\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x\ne3\\x\ne2\end{matrix}\right.\)
`=> (x+1)(x-2)=(x-3)(x+7)`
`=> x^2 -2x +x-2 = x^2+7x-3x-21`
`=> x^2 -x -2 = x^2+4x-21`
`=>x^2 -x-x^2-4x = -21+2`
`=> -5x = -19`
`=>x=19/5` (t/m)
C=\(\dfrac{3}{54}\)+\(\dfrac{5}{126}\)+\(\dfrac{7}{294}\)
\(\dfrac{5}{24}\)+\(\dfrac{5}{104}\)+\(\dfrac{5}{234}\)
\(\dfrac{3}{54}+\dfrac{5}{126}+\dfrac{7}{294}\\ =\dfrac{1}{18}+\dfrac{5}{126}+\dfrac{1}{42}\\ =\dfrac{7}{126}+\dfrac{5}{126}+\dfrac{3}{126}\\ =\dfrac{15}{126}=\dfrac{5}{42}\\ \\ \dfrac{5}{24}+\dfrac{5}{104}+\dfrac{5}{234}\\ =\dfrac{121680}{584064}+\dfrac{28080}{584064}+\dfrac{12480}{584064}\\ =\dfrac{162240}{584064}=\dfrac{5}{18}\)
1 phần 20 + 1 phần 30 + 1phaanf 42 ... + 1 phần 90 = ???
\(\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+...+\dfrac{1}{90}\)
\(=\dfrac{1}{4\cdot5}+\dfrac{1}{5\cdot6}+\dfrac{1}{6\cdot7}+...+\dfrac{1}{9\cdot10}\)
\(=\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+...+\dfrac{1}{9}-\dfrac{1}{10}\)
\(=\dfrac{1}{4}-\dfrac{1}{10}=\dfrac{5-2}{20}=\dfrac{3}{20}\)
x^2 + 2x + 3
x^2+2x+3=x^2+2x+1+2
=(x+1)^2+2>=2
Dấu = xảy ra khi x=-1
\(\dfrac{x}{-8}=\dfrac{2}{-x^3}\) (\(x\ne0\))
Tìm những từ khi soi gương là từ có nghĩa và khi không soi gương vẫn có nghĩa. VD : Tìm \(\Rightarrow\) Mít
Mn tìm 3 từ thôi cũng đc ạ