Question

x(x+32)=6800

tìm x

Answer 1

x(x + 32) = 6800

x² + 32x = 6800

x² + 32x - 6800 = 0

x² + 100x - 68x - 6800 = 0

(x² + 100x) - (68x - 6800) = 0

x(x + 100) - 68(x + 100) = 0

(x + 100)(x - 68) = 0

x + 100 = 0 hoặc x - 68 = 0

*) x + 100 = 0

x = 0 - 100

x = -100

*) x - 68 = 0

x = 0 + 68

x = 68

Vậy x = -100; x = 68

Answer 2

`x^2 + 32x - 6800 = 0`

`<=> (x+100)(x-68) = 0`

`<=> x = -100` hoặc `68`