Question

(x+\(\dfrac{2}{3}\))+\(\dfrac{1}{11}\)=(\(\dfrac{10}{-33}\).\(\dfrac{11}{8}\)).\(\dfrac{24}{-55}\)

Answer 1

\(\left(x+\dfrac{2}{3}\right)+\dfrac{1}{11}=\left(\dfrac{10}{-33}.\dfrac{11}{8}\right).\dfrac{24}{-55}\)

\(\Rightarrow\left(x+\dfrac{2}{3}\right)+\dfrac{1}{11}=\dfrac{-5}{12}.\dfrac{24}{-55}\)

\(\Rightarrow\left(x+\dfrac{2}{3}\right)+\dfrac{1}{11}=\dfrac{2}{11}\)

\(\Rightarrow x+\dfrac{2}{3}=\dfrac{2}{11}-\dfrac{1}{11}\)

\(\Rightarrow x+\dfrac{2}{3}=\dfrac{1}{11}\)

\(\Rightarrow x=\dfrac{1}{11}-\dfrac{2}{3}\)

\(\Rightarrow x=-\dfrac{19}{33}\)

 

Answer 2

(x + 2/3) + 1/11 = [10/(-33) . 11/8] . 24/(-55)

(x + 2/3) + 1/11 = -5/12 . 24/(-55)

(x + 2/3) + 1/11 = 2/11

x + 2/3 = 2/11 - 1/11

x + 2/3 = 1/11

x = 1/11 - 2/3

x = -19/33