Đặt: \(\dfrac{x}{4}=\dfrac{y}{7}=k\)
\(\Rightarrow\left\{{}\begin{matrix}x=4k\\y=7k\end{matrix}\right.\)
Ta có: \(xy=112\Rightarrow4k\cdot7k=112\)
\(\Rightarrow28k^2=112\)
\(\Rightarrow k^2=4\)
\(\Rightarrow\left[{}\begin{matrix}k=-2\\k=2\end{matrix}\right.\)
Với k = -2
\(\Rightarrow\left\{{}\begin{matrix}x=4\cdot-2=-8\\y=7\cdot-2=-14\end{matrix}\right.\)
Với k = 2
\(\Rightarrow\left\{{}\begin{matrix}x=4\cdot2=8\\y=7\cdot2=14\end{matrix}\right.\)