Question

(x+4)(x-4) ≥ (x+3)²+5

Answer 1

\(\left(x+4\right)\left(x-4\right)\ge\left(x+3\right)^2+5\)

\(\Leftrightarrow x^2-16\ge x^2+6x+9+5\)

\(\Leftrightarrow6x\le-30\)

\(\Leftrightarrow x\le-5\)

Answer 2

Cíu

Answer 3

(x + 4)(x - 4) \(\ge\) (x + 3)² + 5

\(\Leftrightarrow x^2-4x+4x-16\ge x^2+6x+9+5\) 

\(\Leftrightarrow x^2-4x+4x-16-x^2-6x-9-5\ge0\)

\(\Leftrightarrow-6x-30\ge0\) 

\(\Leftrightarrow-6x\ge30\) 

\(\Leftrightarrow x\le-5\) 

Vậy pt có tập n_o S = \(\left\{x\uparrow x\le-5\right\}\)