x+4/2000 + x+3/2001 + x+2/2002 + x+1/2003
Sai đề ạ
x+4/2000 + x+3/2001 + x+2/2002 + x+1/2003
Cần gấp ạ!!!
Tìm x:
x + 4/ 2000+ x +3 / 2001= x + 2 / 2002+ x + 1/2001
\(\dfrac{x+4}{2000}+\dfrac{x+3}{2001}=\dfrac{x+2}{2002}+\dfrac{x+1}{2003}\)
x=???
Tìm x biết :
(x+4)/2000 +(x+3)/2001 = (x+2)/2002 +(x+1)/2003
Tìm x, biết:
x+4/2000+x+3/2001=x+2/2002+x+1/2003
(x+4/2000)+(x+3/2001)=(x+2/2002)+(x+1/2003)
tìm x giúp mình nha
(x+4)/2000 + (x+3) /2001 = (x+2)/2002 + (x+1)/2003
tìm số hữu tỉ x
\(x+\frac{4}{2000}+x+\frac{3}{2001}=x+\frac{2}{2002}+x+\frac{1}{2003}\)
\(x+\frac{4}{2000}+x+\frac{3}{2001}=x+\frac{2}{2002}+x+\frac{1}{2003}\)
