\(\Rightarrow\left|x+\dfrac{3}{4}\right|=\dfrac{1}{6}\Rightarrow\left[{}\begin{matrix}x+\dfrac{3}{4}=\dfrac{1}{6}\\x+\dfrac{3}{4}=-\dfrac{1}{6}\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=-\dfrac{7}{12}\\x=-\dfrac{11}{12}\end{matrix}\right.\)
\(\left|x+\dfrac{3}{4}\right|+\dfrac{1}{3}=\dfrac{1}{2}\)
\(\left|x+\dfrac{3}{4}\right|\) \(=\dfrac{1}{2}+\left(\dfrac{-1}{3}\right)=\dfrac{1}{6}\)
\(\text{Vậy }x+\dfrac{3}{4}=\dfrac{1}{6}\)
\(x\) \(=\dfrac{1}{6}+\left(\dfrac{-3}{4}\right)=\dfrac{-7}{12}\)
\(\text{hoặc }x+\dfrac{3}{4}=\dfrac{-1}{6}\)
\(x\) \(=\left(\dfrac{-1}{6}\right)+\left(\dfrac{-3}{4}\right)=\dfrac{-11}{12}\)
\(\Rightarrow x\in\left\{\left(\dfrac{-7}{12}\right);\left(\dfrac{-11}{12}\right)\right\}\)
