\(\dfrac{x+3}{2021}+\dfrac{x+2}{2022}=\dfrac{x-1}{2025}+\dfrac{x-3}{2027}\)
\(\Rightarrow\left(\dfrac{x+3}{2021}+1\right)+\left(\dfrac{x+2}{2022}+1\right)=\left(\dfrac{x-1}{2025}+1\right)+\left(\dfrac{x-3}{2027}+1\right)\)
\(\Rightarrow\dfrac{x+2024}{2021}+\dfrac{x+2024}{2022}-\dfrac{x+2024}{2025}-\dfrac{x+2024}{2027}=0\)
\(\Rightarrow\left(x+2024\right)\left(\dfrac{1}{2021}+\dfrac{1}{2022}-\dfrac{1}{2025}-\dfrac{1}{2027}\right)=0\)
\(\Rightarrow x+2024=0\Rightarrow x=-2024\)
\(\Leftrightarrow\left(\dfrac{x+3}{2021}+1\right)+\left(\dfrac{x+2}{2022}+1\right)=\left(\dfrac{x-1}{2025}+1\right)+\left(\dfrac{x-3}{2027}+1\right)\)
=>x+2024=0
hay x=-2024
