Question

(x³-64)÷(x²+4x+16)

Answer 1

\(\left(x^3-64\right):\left(x^2+4x+16\right)\)

\(=\left(x^3-4^3\right):\left(x^2+4x+16\right)\)

\(=\left(x-4\right)\left(x^2+4x+16\right):\left(x^2+4x+16\right)\)

\(=x-4\)

Answer 2

(x^3-64):(x^2+4x+16)

=(x-4)(x^2+4x+16):(x^2+4x+16)

=x-4