THAM KHẢO
a,x/3 −4/y = 1/5
4/y = x/3 −1/5
4/y = 5x−3/15
=> (5x - 3)y = 15.4 = 60
=> 5x-3 ; y ∈Ư(60)
Mà 5x - 3 chia 5 thiếu 3 (dư 2) nên 5x - 3 ∈{-3;2;12}
=> y ∈ {-20;30;5}
Lặp bảng
Vậy các cặp (x;y) là (0;-20); (1;30); (3;5)
\(\dfrac{x}{3}-\dfrac{4}{y}=\dfrac{1}{5}\)
\(\dfrac{x}{3}=\dfrac{1}{5}+\dfrac{4}{y}\)
\(\dfrac{x}{3}=\dfrac{y+20}{5y}\)
\(x=\dfrac{3y+60}{5y}\)