\(x^3-16x=0\)
\(\left(x^2-16\right)x=0\)
Th1: \(x=0\)
Th2: \(x^2-16=0\)
\(x^2=16\)
\(x=+-4\)
Vậy x=-4; 0; 4
\(x^3-16x=0\)
\(=>x\left(x^2-16\right)=0\)
\(=>\orbr{\begin{cases}x=0\\x^2-16=0\end{cases}}\)
\(=>\orbr{\begin{cases}x=0\\x=+-4\end{cases}}\)
x3-16x=0
=>x2.x-16x=0
=>x2.x=16x
=>x2=16
=>x2=42
=>x=4