Question

x/2=y/3=z/4 và 2x+y-3z=10

Answer 1

\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}=\dfrac{2x+y-3z}{2\cdot2+3-3\cdot4}=\dfrac{10}{-5}=-2\\ \Rightarrow\left\{{}\begin{matrix}a=-4\\b=-6\\c=-8\end{matrix}\right.\)

Answer 2

Áp dụng t/c dtsbn ta có:

\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z}{4}=\dfrac{2x+y-3z}{2.2+3-3.4}=\dfrac{10}{-5}=-2\)

\(\dfrac{x}{2}=-2\Rightarrow x=-4\\ \dfrac{y}{3}=-2\Rightarrow y=-6\\ \dfrac{z}{4}=-2\Rightarrow z=-8\)