TH1: x<-5
=>-x-2-x-3-x-5=12x
=>12x=-3x-10
=>15x=-10
=>x=-2/3(loại)
TH2: -5<=x<-3
=>-x-2-x-3+x+5=12x
=>12x=-x
=>x=0(loại)
Th3: -3<=x<-2
=>-x-2+x+3+x+5=12x
=>12x=x+6
=>11x=6
=>x=6/11(loại)
TH4: x>=-2
=>12x=x+2+x+3+x+5=3x+10
=>9x=10
=>x=10/9(nhận)
2x-5=1
2x(x+2)-3(x+2)=0
5/x-3 +
-4/x+3=x-5/x^2-9
1 .[(x+)^5-2(x+y)^4]:[-5(x+y)^3]
2.phân tích đa thức thành nt
a,12x^3-12x^2+3x
b,x^2(x-1)+9(1-x)
c,8(x-y)-x^3(x-y)
3.tìm x
x^2+1/4=x
Biết \(x^2-2x-1=0\). Tính biểu thức \(\dfrac{x^6-6x^5+12x^4-8x^3+2015}{x^6-8x^3-12x^2+6x+2015}\)
Giải pt bậc bốn sau
2x^4-x^3-9x^2+13x-5=0
x^4-2x^3-11x^2+12x+36=0
x^4-12x^3+x^2+x+1=0
phan tich da thuc thanh nhan tu:
a,x^4-2x^3-12x^2+12x+36
b,x^4+x^3+6x^2+5x+5
c,x^8y^8+x^4y^4+1
d,x^5-x^4+x^3-X^2+x-1
e,x^5+x^4-X63+x62-x+2
g,x(Y^2-z^2)+y(z^2-x^2)+z(x^2-y^2)
tim x (X/2+3)(5-6X)+(12X-2)(X/4+3)=0
1.(2x-2)^2=(x+1)^2+(x-2)(x+5)
2.2x(x+5)-(x-3)^2=x^2+6
3.(x+2)^3-(x-2)^3=12x(x-1)-8
(x/2+3)(5-6x)+12x-2+(x/4+3)=0
Tìm x
(x/2+3)(5-6x)+12x-2+(x/4+3)=0
Tìm x
