Question

(x+2)(x+1)-(x-3)(x+2)=0

Answer 1

\(\left(x+2\right)\left(x+1\right)-\left(x-3\right)\left(x+2\right)=0\)

\(x^2+3x+2-\left(x^2-x-6\right)=0\)

\(x^2+3x+2-x^2+x+6=0\)

\(4x+8=0\)

\(4x=-8\)

\(x=-2\)

Answer 2

\(\left(x+2\right)\left(x+1\right)-\left(x-3\right)\left(x+2\right)=0\\ =>\left(x+2\right)\left(x+1-x+3\right)=0\\ =>\left(x+2\right).4=0\\ =>x+2=0\\ =>x=-2\)

Answer 3

\(\left(x+2\right)\left(x+1\right)-\left(x-3\right)\left(x+2\right)=0\)

\(x^2+x+2x+2-\left(x^2+2x-3x-6\right)=0\)

\(x^2+x+2x+2-x^2-2x+3x+6=0\)

\(\left(x^2-x^2\right)+\left(x+2x-2x+3x\right)+\left(2+6\right)=0\)

\(4x+8=0\)

\(4x\)       \(=0-8=-8\)

  \(x\)       \(\left(-8\right):4=-2\)