Question

x^2+4x-5

Answer 1

\(x^2+4x-5\\ =x^2+5x-x-5\\ =\left(x^2+5x\right)-\left(x+5\right)\\ =x\left(x+5\right)-\left(x+5\right)\\ =\left(x-1\right)\left(x+5\right)\)

Answer 2

`x^2 + 4x -5`

`= x^2 + 2.x.2 + 4 - 9`

`= (x + 2)^2 - 9`

`= (x+2)^2 - 3^2`

`=(x+2-3)(x+2+3)`

`=(x-1)(x+5)`